Optimal. Leaf size=252 \[ -\frac {\left (\frac {25}{16}+\frac {21 i}{16}\right ) \text {ArcTan}\left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} a^2 d}+\frac {\left (\frac {25}{16}+\frac {21 i}{16}\right ) \text {ArcTan}\left (1+\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} a^2 d}-\frac {25 \sqrt {\cot (c+d x)}}{8 a^2 d}+\frac {7 \cot ^{\frac {3}{2}}(c+d x)}{8 a^2 d (i+\cot (c+d x))}+\frac {\cot ^{\frac {5}{2}}(c+d x)}{4 d (i a+a \cot (c+d x))^2}-\frac {\left (\frac {25}{32}-\frac {21 i}{32}\right ) \log \left (1-\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{\sqrt {2} a^2 d}+\frac {\left (\frac {25}{32}-\frac {21 i}{32}\right ) \log \left (1+\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{\sqrt {2} a^2 d} \]
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Rubi [A]
time = 0.25, antiderivative size = 252, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 11, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.423, Rules used = {3754, 3639,
3676, 3609, 3615, 1182, 1176, 631, 210, 1179, 642} \begin {gather*} -\frac {\left (\frac {25}{16}+\frac {21 i}{16}\right ) \text {ArcTan}\left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} a^2 d}+\frac {\left (\frac {25}{16}+\frac {21 i}{16}\right ) \text {ArcTan}\left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2} a^2 d}+\frac {7 \cot ^{\frac {3}{2}}(c+d x)}{8 a^2 d (\cot (c+d x)+i)}-\frac {25 \sqrt {\cot (c+d x)}}{8 a^2 d}-\frac {\left (\frac {25}{32}-\frac {21 i}{32}\right ) \log \left (\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2} a^2 d}+\frac {\left (\frac {25}{32}-\frac {21 i}{32}\right ) \log \left (\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2} a^2 d}+\frac {\cot ^{\frac {5}{2}}(c+d x)}{4 d (a \cot (c+d x)+i a)^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 210
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 1182
Rule 3609
Rule 3615
Rule 3639
Rule 3676
Rule 3754
Rubi steps
\begin {align*} \int \frac {\cot ^{\frac {3}{2}}(c+d x)}{(a+i a \tan (c+d x))^2} \, dx &=\int \frac {\cot ^{\frac {7}{2}}(c+d x)}{(i a+a \cot (c+d x))^2} \, dx\\ &=\frac {\cot ^{\frac {5}{2}}(c+d x)}{4 d (i a+a \cot (c+d x))^2}+\frac {\int \frac {\cot ^{\frac {3}{2}}(c+d x) \left (-\frac {5 i a}{2}+\frac {9}{2} a \cot (c+d x)\right )}{i a+a \cot (c+d x)} \, dx}{4 a^2}\\ &=\frac {7 \cot ^{\frac {3}{2}}(c+d x)}{8 a^2 d (i+\cot (c+d x))}+\frac {\cot ^{\frac {5}{2}}(c+d x)}{4 d (i a+a \cot (c+d x))^2}+\frac {\int \sqrt {\cot (c+d x)} \left (-\frac {21 i a^2}{2}+\frac {25}{2} a^2 \cot (c+d x)\right ) \, dx}{8 a^4}\\ &=-\frac {25 \sqrt {\cot (c+d x)}}{8 a^2 d}+\frac {7 \cot ^{\frac {3}{2}}(c+d x)}{8 a^2 d (i+\cot (c+d x))}+\frac {\cot ^{\frac {5}{2}}(c+d x)}{4 d (i a+a \cot (c+d x))^2}+\frac {\int \frac {-\frac {25 a^2}{2}-\frac {21}{2} i a^2 \cot (c+d x)}{\sqrt {\cot (c+d x)}} \, dx}{8 a^4}\\ &=-\frac {25 \sqrt {\cot (c+d x)}}{8 a^2 d}+\frac {7 \cot ^{\frac {3}{2}}(c+d x)}{8 a^2 d (i+\cot (c+d x))}+\frac {\cot ^{\frac {5}{2}}(c+d x)}{4 d (i a+a \cot (c+d x))^2}+\frac {\text {Subst}\left (\int \frac {\frac {25 a^2}{2}+\frac {21}{2} i a^2 x^2}{1+x^4} \, dx,x,\sqrt {\cot (c+d x)}\right )}{4 a^4 d}\\ &=-\frac {25 \sqrt {\cot (c+d x)}}{8 a^2 d}+\frac {7 \cot ^{\frac {3}{2}}(c+d x)}{8 a^2 d (i+\cot (c+d x))}+\frac {\cot ^{\frac {5}{2}}(c+d x)}{4 d (i a+a \cot (c+d x))^2}+\frac {\left (\frac {25}{16}-\frac {21 i}{16}\right ) \text {Subst}\left (\int \frac {1-x^2}{1+x^4} \, dx,x,\sqrt {\cot (c+d x)}\right )}{a^2 d}+\frac {\left (\frac {25}{16}+\frac {21 i}{16}\right ) \text {Subst}\left (\int \frac {1+x^2}{1+x^4} \, dx,x,\sqrt {\cot (c+d x)}\right )}{a^2 d}\\ &=-\frac {25 \sqrt {\cot (c+d x)}}{8 a^2 d}+\frac {7 \cot ^{\frac {3}{2}}(c+d x)}{8 a^2 d (i+\cot (c+d x))}+\frac {\cot ^{\frac {5}{2}}(c+d x)}{4 d (i a+a \cot (c+d x))^2}+\frac {\left (\frac {25}{32}+\frac {21 i}{32}\right ) \text {Subst}\left (\int \frac {1}{1-\sqrt {2} x+x^2} \, dx,x,\sqrt {\cot (c+d x)}\right )}{a^2 d}+\frac {\left (\frac {25}{32}+\frac {21 i}{32}\right ) \text {Subst}\left (\int \frac {1}{1+\sqrt {2} x+x^2} \, dx,x,\sqrt {\cot (c+d x)}\right )}{a^2 d}+-\frac {\left (\frac {25}{32}-\frac {21 i}{32}\right ) \text {Subst}\left (\int \frac {\sqrt {2}+2 x}{-1-\sqrt {2} x-x^2} \, dx,x,\sqrt {\cot (c+d x)}\right )}{\sqrt {2} a^2 d}+-\frac {\left (\frac {25}{32}-\frac {21 i}{32}\right ) \text {Subst}\left (\int \frac {\sqrt {2}-2 x}{-1+\sqrt {2} x-x^2} \, dx,x,\sqrt {\cot (c+d x)}\right )}{\sqrt {2} a^2 d}\\ &=-\frac {25 \sqrt {\cot (c+d x)}}{8 a^2 d}+\frac {7 \cot ^{\frac {3}{2}}(c+d x)}{8 a^2 d (i+\cot (c+d x))}+\frac {\cot ^{\frac {5}{2}}(c+d x)}{4 d (i a+a \cot (c+d x))^2}-\frac {\left (\frac {25}{32}-\frac {21 i}{32}\right ) \log \left (1-\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{\sqrt {2} a^2 d}+\frac {\left (\frac {25}{32}-\frac {21 i}{32}\right ) \log \left (1+\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{\sqrt {2} a^2 d}+-\frac {\left (\frac {25}{16}+\frac {21 i}{16}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} a^2 d}+\frac {\left (\frac {25}{16}+\frac {21 i}{16}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} a^2 d}\\ &=-\frac {\left (\frac {25}{16}+\frac {21 i}{16}\right ) \tan ^{-1}\left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} a^2 d}+\frac {\left (\frac {25}{16}+\frac {21 i}{16}\right ) \tan ^{-1}\left (1+\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} a^2 d}-\frac {25 \sqrt {\cot (c+d x)}}{8 a^2 d}+\frac {7 \cot ^{\frac {3}{2}}(c+d x)}{8 a^2 d (i+\cot (c+d x))}+\frac {\cot ^{\frac {5}{2}}(c+d x)}{4 d (i a+a \cot (c+d x))^2}-\frac {\left (\frac {25}{32}-\frac {21 i}{32}\right ) \log \left (1-\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{\sqrt {2} a^2 d}+\frac {\left (\frac {25}{32}-\frac {21 i}{32}\right ) \log \left (1+\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{\sqrt {2} a^2 d}\\ \end {align*}
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Mathematica [A]
time = 1.25, size = 232, normalized size = 0.92 \begin {gather*} -\frac {\cot ^{\frac {3}{2}}(c+d x) \csc (c+d x) \sec ^2(c+d x) \left (23 \cos (c+d x)+41 \cos (3 (c+d x))+43 i \sin (c+d x)-(25-21 i) \cos (2 (c+d x)) \log \left (\cos (c+d x)+\sin (c+d x)+\sqrt {\sin (2 (c+d x))}\right ) \sqrt {\sin (2 (c+d x))}-(21+25 i) \log \left (\cos (c+d x)+\sin (c+d x)+\sqrt {\sin (2 (c+d x))}\right ) \sin ^{\frac {3}{2}}(2 (c+d x))+(21-25 i) \text {ArcSin}(\cos (c+d x)-\sin (c+d x)) \sqrt {\sin (2 (c+d x))} (-i \cos (2 (c+d x))+\sin (2 (c+d x)))+43 i \sin (3 (c+d x))\right )}{32 a^2 d (i+\cot (c+d x))^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 4 vs. order
3.
time = 13.89, size = 1261, normalized size = 5.00
method | result | size |
default | \(\text {Expression too large to display}\) | \(1261\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 509 vs. \(2 (187) = 374\).
time = 0.53, size = 509, normalized size = 2.02 \begin {gather*} \frac {{\left (4 \, a^{2} d \sqrt {\frac {i}{16 \, a^{4} d^{2}}} e^{\left (4 i \, d x + 4 i \, c\right )} \log \left (2 \, {\left (4 \, {\left (a^{2} d e^{\left (2 i \, d x + 2 i \, c\right )} - a^{2} d\right )} \sqrt {\frac {i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} - 1}} \sqrt {\frac {i}{16 \, a^{4} d^{2}}} + i \, e^{\left (2 i \, d x + 2 i \, c\right )}\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}\right ) - 4 \, a^{2} d \sqrt {\frac {i}{16 \, a^{4} d^{2}}} e^{\left (4 i \, d x + 4 i \, c\right )} \log \left (-2 \, {\left (4 \, {\left (a^{2} d e^{\left (2 i \, d x + 2 i \, c\right )} - a^{2} d\right )} \sqrt {\frac {i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} - 1}} \sqrt {\frac {i}{16 \, a^{4} d^{2}}} - i \, e^{\left (2 i \, d x + 2 i \, c\right )}\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}\right ) + 4 \, a^{2} d \sqrt {-\frac {529 i}{64 \, a^{4} d^{2}}} e^{\left (4 i \, d x + 4 i \, c\right )} \log \left (\frac {{\left (8 \, {\left (a^{2} d e^{\left (2 i \, d x + 2 i \, c\right )} - a^{2} d\right )} \sqrt {\frac {i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} - 1}} \sqrt {-\frac {529 i}{64 \, a^{4} d^{2}}} + 23 i\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}}{8 \, a^{2} d}\right ) - 4 \, a^{2} d \sqrt {-\frac {529 i}{64 \, a^{4} d^{2}}} e^{\left (4 i \, d x + 4 i \, c\right )} \log \left (-\frac {{\left (8 \, {\left (a^{2} d e^{\left (2 i \, d x + 2 i \, c\right )} - a^{2} d\right )} \sqrt {\frac {i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} - 1}} \sqrt {-\frac {529 i}{64 \, a^{4} d^{2}}} - 23 i\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}}{8 \, a^{2} d}\right ) - \sqrt {\frac {i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} - 1}} {\left (42 \, e^{\left (4 i \, d x + 4 i \, c\right )} - 9 \, e^{\left (2 i \, d x + 2 i \, c\right )} - 1\right )}\right )} e^{\left (-4 i \, d x - 4 i \, c\right )}}{16 \, a^{2} d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} - \frac {\int \frac {\cot ^{\frac {3}{2}}{\left (c + d x \right )}}{\tan ^{2}{\left (c + d x \right )} - 2 i \tan {\left (c + d x \right )} - 1}\, dx}{a^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\mathrm {cot}\left (c+d\,x\right )}^{3/2}}{{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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